Defensive Programming

Last updated on 2025-04-15 | Edit this page

Overview

Questions

How can I catch errors in my data?
How can I make best use of error messages?

Objectives

Learn how to catch and deal with errors within your code.
Learn how to catch problematic data before it is used in your code.

In this episode we are going to learn about error handling, a python structure (also common in other programming languages) which will help us to properly manage the anomalies that can be encountered when executing our code.

In science most developers write code for themselves and do not feel the need to use error handling. However, nowadays scientists have to share their work as more funding agencies are also asking for the code used in experiments to be published.

More importantly, applications are not expected to crash and we are going to learn how to avoid this non desirable behaviour.

What is the problem with this test?

Please look at the following code. Can you find the fundamental problem in this test?

BASH

val = 1

if val>0 and val<10:
    print('Value: ', val, 'is a digit.')
elif val==0:
    print('Value ', val, 'is nul')
else:
    print('Value: ', val, 'is a number.')

Show me the solution

The test assumes that val is a number, and throws an uncontrolled error if it is not.

BASH

val = 'a'

if val>0 and val<10:
    print('Value: ', val, 'is a digit.')
elif val==0:
    print('Value ', val, 'is nul')
else:
    print('Value: ', val, 'is a number.')

OUTPUT

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-2-99c0e25bf5e9> in <module>()
      1 val = 'a'
      2
----> 3 if val>0 and val<10:
      4     print('Value: ', val, 'is a digit.')
      5 elif val==0:

TypeError: '>' not supported between instances of 'str' and 'int'

We can avoid problems like this by wrapping our code in an if statement:

PYTHON

if type(val) is int or type(val) is float:
    if val>0 and val<10:
        print('Value: ', val, 'is a digit.')
    elif val==0:
        print('Value ', val, 'is nul')
    else:
        print('Value: ', val, 'is a number.')
else:
    print('val is not a number')

However, this becomes tedious to implement very quickly, especially when trying to cover a number of possible errors, which will all need their own if clauses. This can lead to a lot of duplicated code, making the code difficult to maintain.

Python provides the try-except structure to avoid this issue, enabling developers to properly manage any possible errors. The basic try-except structure is:

PYTHON

try:
    if val>0 and val<10:
        print('Value: ', val, 'is a digit.')
    elif val==0:
        print('Value ', val, 'is nul')
    else:
        print('Value: ', val, 'is a number.')
except:
    print('Val is not a number')
    print('Enter a new number')

At the top of the statement is the code that we are interested in executing, which is run in the try statement. If that fails then the except statement comes into effect, (hopefully) returning helpful information to the user about what happened and giving them some guidance on how to avoid the problem in future.

The except statement will catch all errors and so we do not, initially at least, need to know exactly what errors we are trying to avoid. However, python does provide error codes, which we can use to expand the structure to capture specific error types. For the example above, we would want to capture a TypeError:

PYTHON

try:
    if val>0 and val<10:
        print('Value: ', val, 'is a digit.')
    elif val==0:
        print('Value ', val, 'is nul')
    else:
        print('Value: ', val, 'is a number.')
except TypeError as err:
    print('Val is not a number')
    print('But our code does not crash anymore')
    print('The run-time error is:', err)

As with if statements, multiple except statements can be used, each with a different error test. These can be followed by an (optional) catch-all bare except statement (as we started with) to catch any unexpected errors. Note that only one try statement is allowed in the structure.

try-except structures may also contain else and finally statements (following in order after the except statements). The else statement will be executed if no except statements are executed, while the finally statement will be executed after all other statements are finished.

PYTHON

try:
    if val>0 and val<10:
        print('Value: ', val, 'is a digit.')
    elif val==0:
        print('Value ', val, 'is nul')
    else:
        print('Value: ', val, 'is a number.')
except TypeError as err:
    print('Val is not a number')
    print('But our code does not crash anymore')
    print('The run-time error is:', err)
else:
    print('1/val = ', 1/val)
finally:
    print('release memory')
    del(val)

The typical use of the finally statement is to deal with the release of external resources (such as files or network connections) whether or not the attempted action has been successful.

More details about errors and exceptions can be found in the Python tutorials.

HTTP errors

Earlier we were introduced to the requests library. This is used to access web content, and returns a code indicating the request status. The raise_for_status function is provided for testing the request status, which returns a request.HTTPError if there is an error. For example, if we request a missing webpage we get this error:

PYTHON

import requests

source_url='https://api.datacite.org/dois/10.48546/workflowhub.workflow.56.1000'
response = requests.get(source_url)
response.raise_for_status()

OUTPUT

Traceback (most recent call last):

  File "<ipython-input-108-06c23faa067a>", line 3, in <module>
    response.raise_for_status()


  File "/Users/mbessdl2/anaconda3/envs/myenv/lib/python3.9/site-packages/requests/models.py", line 943, in raise_for_status
    raise HTTPError(http_error_msg, response=self)

HTTPError: 404 Client Error: Not Found for url: https://api.datacite.org/dois/10.48546/workflowhub.workflow.56.1000

Write a try-except structure that uses raise_for_status and deals with the error without crashing.

Show me the solution

PYTHON

import requests

try:
    source_url='https://api.datacite.org/dois/10.48546/workflowhub.workflow.56.1000'
    response = requests.get(source_url)
    response.raise_for_status()
except requests.HTTPError as err:
    print(err)

OUTPUT

404 Client Error: Not Found for url: https://api.datacite.org/dois/10.48546/workflowhub.workflow.56.1000

Assert

The try-except structure is useful for controlling small chunks of code, where we might reasonably expect that the user can fix the problem (where it is a program which takes a short time to run), or where our program itself will fix the problem (such as substituting NaN values for a failed calculation).

Sometimes, however, it is better to check the data before it is passed into the code and to trigger an early crash in the program, which returns a meaningful error. For example, this can be extremely useful in the case of large numerical calculations that take a long time to run and which will only use some of the provided variables after a significant amount of the computational work has already been carried out. In such situations your user will appreciate being warned early on that they have provided invalid data.

To conduct such a test we can use an assert statement. This follows the structure: assert <test>, <error message>. As an example of this, we can write the test for non-numerical values as:

PYTHON

val = 'a'

assert type(val) is float or type(val) is int, "Variable has to be a numerical object"

if val>0 and val<10:
    print('Value: ', val, 'is a digit.')
elif val==0:
    print('Value ', val, 'is nul')
else:
    print('Value: ', val, 'is a number.')

OUTPUT

Traceback (most recent call last):

  File "<ipython-input-38-52d27526daab>", line 1, in <module>
    assert type(val) is float or type(val) is int, "Variable has to be a numerical object"

AssertionError: Variable has to be a numerical object

Like the earlier if statement, this catches the problematic variable before it reaches our calculation. However it is far less intrusive code, and assert tests can be added in sequence, so that we can quickly and easily increase the coverage of such tests.

Testing for NaN’s (Not a Number)

Numpy provides Not a Number (nan) values, which can be used to indicate missing data. These are not caught by the test above:

PYTHON

import numpy as np

val = np.nan

assert type(val) is float or type(val) is int, "Variable has to be a numerical object"

if val>0 and val<10:
  print('Value: ', val, 'is a digit.')
elif val==0:
  print('Value ', val, 'is nul')
else:
  print('Value: ', val, 'is a number.')

OUTPUT

Value:  nan is a number.

However numpy does provide the isnan() function for testing if a value is NaN. Add an assertion test using this which will raise and error if the value is NaN.

Show me the solution

Because the test checks if a value is NaN, we need to add not before the test, to ensure that the assert statement fails if it is a NaN:

PYTHON

import numpy as np

val = np.nan

assert type(val) is float or type(val) is int, "Variable has to be a numerical object"
assert not np.isnan(val), "Variable must not be a NaN"

if val>0 and val<10:
    print('Value: ', val, 'is a digit.')
elif val==0:
    print('Value ', val, 'is nul')
else:
    print('Value: ', val, 'is a number.')

OUTPUT

Traceback (most recent call last):

  File "<ipython-input-52-553a9c93f77a>", line 4, in <module>
    assert not np.isnan(val), "Variable must not be a NaN"

AssertionError: Variable must not be a NaN

Key Points

try-except structures are useful for catching errors as they occur
assert structures are useful for forcing errors early, to avoid wasted effort